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Showing results - 201 to 210 of 211
Working With the Discriminant First
02:26

Working With the Discriminant First

Work with the discriminant first because it determines whether or not the equation has a solution. If the discriminant is positive, the equation has two solutions. If the discriminant is negative, the equation has not solution. Examples of both are ...

Word Problems Simplified by Using Algebra
01:13

Word Problems Simplified by Using Algebra

How to translate word problems into algebraic equations.

A System with No Solution and a System with Infinite Solutions
02:32

A System with No Solution and a System with Infinite Solutions

Presented is a system of equations to which there is no solution the lines are parallel and a system of equations to which the solution is coincident lines the two equations share the same, infinite number of solutions.

Writing Algebraic Expressions
01:25

Writing Algebraic Expressions

Introducing different ways to write algebraic expressions.

Writing an Equation for a Word Problem
02:59

Writing an Equation for a Word Problem

Develop and solve an equation based on the information provided in a word problem.

Equation Defined
00:29

Equation Defined

The definition of an equation.

Multiplicative Inverses
02:29

Multiplicative Inverses

Every number has an additive inverse. The concept of inverses in algebra is explained and the use of additive inverses is demonstrated.

Using the Discriminant to Calculate Income from Mug Sales
07:14

Using the Discriminant to Calculate Income from Mug Sales

Using the discriminant to solve a practical problem involving the pricing of mugs for greatest profit.

Using the Least Common Denominator to Solve an Equation
00:36

Using the Least Common Denominator to Solve an Equation

Review of the procedure for solving equations that contain rational expressions.

When to Factor Instead of Using the Quadratic Formula
01:22

When to Factor Instead of Using the Quadratic Formula

It makes sense to factor instead of using the quadratic formula when it's easy to find two numbers whose sum is the same as the middle term's coefficient and whose product is equal to the leading coefficient multiplied by the last term. An example i...