Practical Problem: Pricing a Product and Maximizing Profit
Using a quadratic equation with two variables to solve a practical problem involving product pricing.
Approximating the Value of a Solution
Sometimes it makes sense to approximate the value of a solution. An example is given and the solution found.
Solve: 2x2 - 15x 18 = 0
Practice solving a quadratic equation: 2x2 - 15x 18 = 0
Equation That Has No Solution, An
An equation is found to have no solution after using the least common denominator to get a quadratic equation.
Estimating Radicals to Set a Safe Speed Limit
A practical problem involving setting a speed limit is solved that involves estimating radicals to find the value of an irrational solution.
Using a Quadratic Equation to Calculate What Size Driveway Will Fit Within the Budget
Using the quadratic equation to solve a practical problem that involves finding calculating the width and length a driveway can be given a budgeted amount of money.
Solve: x2 - 8x 16 = 0
Practice solving a quadratic equation: x2 8x 16 = 0. Because this equation has two identical binomial factors, it has a single solution called a double root.
Solve: 12x2 7x - 10 = 0
Solving a quadratic equation in which the trinomial has a leading coefficient other than one.
Working With the Discriminant First
Work with the discriminant first because it determines whether or not the equation has a solution. If the discriminant is positive, the equation has two solutions. If the discriminant is negative, the equation has not solution. Examples of both are ...
Using the Discriminant to Calculate Income from Mug Sales
Using the discriminant to solve a practical problem involving the pricing of mugs for greatest profit.