Practice solving a quadratic equation: 2x2 - 15x 18 = 0
Subject: sum
Transcript: SUM MUST BE NEGATIVE 15. LET'S SEE, NEGATIVE 12 AND NEGATIVE 3 WILL WORK. WE'LL USE NEGATIVE 12 AND NEGATIVE 3 TO EXPAND THE MIDDLE TERM. NOW WE CAN
This clip explains that the median is the number in the middle of the data set when values are put in a numerically ordered sequence called an array. If the data set contains an outlier, the median may be a better statistic to use than the mean. As ...
Subject: sum
A quadratic trinomial in which the last term is negative is factored.
Subject: sum
Transcript: NUMBERS THAT WILL GIVE US A PRODUCT OF NEGATIVE 24 AND A SUM OF POSITIVE 5. TO GET A NEGATIVE PRODUCT, ONE OF THE NUMBERS WILL HAVE TO BE POSITIVE. THE
The distributive law of multiplication over subtraction defined and explained.
Subject: sum
Transcript: VERY OFTEN. NOW WE CAN STATE THE DISTRIBUTIVE LAW. IF WE HAVE THE SUM OF TWO TERMS, CALL THEM B AND C, AND IF WE'RE MULTIPLYING THIS SUM BY ANOTHER
Practice solving a quadratic equation: x2 8x 16 = 0. Because this equation has two identical binomial factors, it has a single solution called a double root.
Subject: sum
Transcript: TRINOMIAL, WE NEED TWO NUMBERS WHOSE PRODUCT IS 16 AND WHOSE SUM IS NEGATIVE 8. THOSE NUMBERS ARE NEGATIVE 4 AND NEGATIVE 4. THE FACTORS OF THE TRINOMIAL ARE
Solving a quadratic equation in which the trinomial has a leading coefficient other than one.
Subject: sum
Transcript: EQUAL TO THE LAST TERM MULTIPLIED BY THE COEFFICIENT OF THE FIRST TERM. THAT'S NEGATIVE 10 TIMES 12, OR NEGATIVE 120. THE SAME TWO NUMBERS MUST HAVE A SUM
The standard form for any quadratic trinomial is ax2 bx c.
Subject: sum
Transcript: FORM. THAT WAY WHEN WE FACTOR WE WON'T HAVE ANY QUESTION ABOUT WHICH TERMS TO USE FOR THE PRODUCT AND THE SUM OF THE TWO NUMBERS WE'RE LOOKING FOR.
It makes sense to factor instead of using the quadratic formula when it's easy to find two numbers whose sum is the same as the middle term
Subject: sum
Transcript: WHOSE SUM IS THE SAME AS THE MIDDLE TERM'S COEFFICIENT AND WHOSE PRODUCT IS EQUAL TO THE LEADING COEFFICIENT MULTIPLIED BY THE LAST TERM. TO FACTOR, WE