Radicand Divided by Another Radicand, A
Simplifying a radical expression by dividing the radical in the numerator by the radical in the denominator.
Subject: factor
Transcript: SIMPLIFIED. NOW THE SQUARE ROOT OF 3 APPEARS IN THE NUMERATOR AND THE DENOMINATOR. WE CAN CANCEL THESE FACTORS JUST AS WE WOULD IN ANY FRACTION. THE ANSWER IS
Practical Problem: How Much Land to Buy
A practical problem involving the purchase of land is presented. The available information is organized into a table, an equation is written, then solved using the least common denominator to get a quadratic equation, and the solution checked.
Subject: factor
Transcript: DENOMINATOR OF THE FRACTIONS. IT'S X TIMES X MINUS 100. SO WE'LL MULTIPLY BOTH SIDES OF THE EQUATION BY THESE TWO FACTORS. WE'LL BEGIN ON THE LEFT SIDE. HERE
Simplifying the Square Root of Larger Numbers
Simplifying the square root of a larger number.
Subject: factor
Transcript: LET'S SIMPLIFY THE SQUARE ROOT OF A LARGER NUMBER. FIND THE SQUARE ROOT OF 720. SUPPOSE WE START WITH THE FACTORS 9 AND 80. THE SQUARE ROOT OF 9 IS
Factor: 3c2 - 13cd 14d2
Practice factoring a trinomial with two different variables: 3c2 - 13cd 14d2.
Series: Factoring, Part Three
Subject: factor
Transcript: HERE'S ANOTHER TRINOMIAL WITH TWO DIFFERENT VARIABLES. WE CAN FACTOR IT IN A WAY THAT'S SIMILAR TO FACTORING QUADRATIC TRINOMIALS WITH A LEADING
Factor: 5y2 6y 5xy 6x
Practice factoring: 5y2 6y 5xy 6x.
Series: Factoring, Part Two
Subject: factor
Transcript: TRY FACTORING THIS POLYNOMIAL YOURSELF. INSPECT THE TERMS CAREFULLY BEFORE YOU GROUP THEM. WE CAN GROUP THE FIRST TWO TERMS AND THE LAST TWO TERMS
Solving a Quadratic Equation Using the Quadratic Formula
Quadratic equations that cannot be solved by factoring or the square root method can be solved using the quadratic formula. When an equation is in
Subject: factor
Transcript: WE'LL LEARN HOW TO SOLVE QUADRATIC EQUATIONS THAT CANNOT BE SOLVED BY FINDING SQUARE ROOTS OR BY FACTORING. HERE'S AN EXAMPLE. WE DON'T HAVE PERFECT
Factor: a2 12a 27
Demonstration of a shortcut that can be used to factor a quadratic trinomial with a leading coefficient of 1.
Series: Factoring, Part Three
Subject: factor
Transcript: WHEN WE FACTOR QUADRATIC TRINOMIALS WITH A LEADING COEFFICIENT OF 1, WE CAN TAKE A SHORTCUT. THE FIRST TERM IN EACH BINOMIAL FACTOR WILL BE THE
Factor: 9y2 - 15y 4
Practice factoring a trinomial with a negative middle term: 9y2 - 15x 4.
Series: Factoring, Part Three
Subject: factor
Transcript: HERE'S ANOTHER TRINOMIAL WITH A NEGATIVE MIDDLE TERM. WE'LL BE CAREFUL WITH SIGNS AS WE FACTOR BY GROUPING. WE WANT TWO NUMBERS WHOSE PRODUCT EQUALS
Factor: 8a2 10a 3
Practice factoring: 8a2 10a 3.
Series: Factoring, Part Three
Subject: factor
Transcript: LET'S FACTOR THIS TRINOMIAL. WE'LL START BY LOOKING FOR TWO NUMBERS WHOSE SUM IS THE COEFFICIENT OF THE MIDDLE TERM, THAT'S 10. THE TWO NUMBERS MUST
Factor: xy 7x 7y x2
Practice factoring: xy 7x 7y x2. Two different factorable groups are demonstrated.
Series: Factoring, Part Two
Subject: factor
Transcript: SOMETIMES WE'LL HAVE TO REARRANGE TERMS IN ORDER TO FACTOR BY GROUPING. FOR EXAMPLE, IN THIS POLYNOMIAL WE CAN'T GROUP THE FIRST TWO TERMS AND THE