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Solving Systems with Fractions in the Equations
03:25

Solving Systems with Fractions in the Equations

Systems of equations that contain fractions can be difficult to work with. Clearing the fractions in such a system by multiplying each equation by the least common denominator of the fractions in the equation can be a go..

Solving Systems with Substitution
03:03

Solving Systems with Substitution

An introduction to using the algebraic method of substitution to solve a system of equations in which one of the equations is not in slope-intercept form.

Solving Systems with Substitution Example
01:10

Solving Systems with Substitution Example

The substitution method can be used when one of the equations in a system has been solved for one of its variables. An example demonstrates.

Solving a Basic Algebraic Equation
02:15

Solving a Basic Algebraic Equation

The definition of an algebraic equation and how to solve it, using a practical example.

Solving a Complicated Cash Register Problem
03:19

Solving a Complicated Cash Register Problem

A store manager needs to calculate how many bills of each denomination she can get with $100 in order to begin the day with enough change in her cash register, knowing she needs only one $20 bill. The solution is present..

Solving a Complicated Mixture Problem
03:45

Solving a Complicated Mixture Problem

A complicated word problem involving percentages is broken into simpler parts and a solution found.

Solving a Complicated Principal, Rate, and Interest Problem
03:52

Solving a Complicated Principal, Rate, and Interest Problem

Two loans with different interest rates and terms are compared to find the one that fits with the borrower's budget for interest.

Solving a Consecutive Number Problem
03:12

Solving a Consecutive Number Problem

Writing an equation to solve a word problem, then solving the equation and checking the answer.

Solving a Mixture Problem Using One Variable
03:12

Solving a Mixture Problem Using One Variable

A word problem involving mixing a solution that needs to be 25 percent chlorine is analyzed, the unknown identified, and a one-variable equation written to solve the problem.

Solving a Mixture Problem Using Two Variables
04:25

Solving a Mixture Problem Using Two Variables

A word problem involving mixing a solution that needs to be 25 percent chlorine is analyzed, the unknown identified, and a two-variable system of equations written to solve the problem.

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